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[主观题]
某台浮选机共4室,每室20M3已知矿浆入料浓度为20%,浮选时间为8分钟,如果浮选机的容积利用系数为0.7,请计算此台浮选机的处理量和单位容积处理能力(煤泥密度为1.3g/cm3)
提问人:网友lixin080108
发布时间:2022-01-26
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由题意可知n=4,V=20M3,P=20%,t=8分钟,K=0.7,ρ=1.3g/cm3;
因为P=100/(R+1)=20
R=(100—P)/P=4
浮选机的处理量Q=60nVK/(R+1/ρ)T
=60×4×20×0.7/(4+1/1.3)8=3360/38.15=88.07t/h·台单位容积处理能力q=Q/nVK=88.07/(4×20×0.7)=88.07/56=1.57t/h·m3
此台浮选机的处理量是88.07t/h·台,单位容积处理能力是1.57t/h·m3
因为P=100/(R+1)=20
R=(100—P)/P=4
浮选机的处理量Q=60nVK/(R+1/ρ)T
=60×4×20×0.7/(4+1/1.3)8=3360/38.15=88.07t/h·台单位容积处理能力q=Q/nVK=88.07/(4×20×0.7)=88.07/56=1.57t/h·m3
此台浮选机的处理量是88.07t/h·台,单位容积处理能力是1.57t/h·m3
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