A.<class 'str'>
B.<class 'tuple'>
C.(class 'str')
D.(class 'tuple')
A.<class 'str'>
B.<class 'tuple'>
C.(class 'str')
D.(class 'tuple')
请问以下代码有什么问题:
int main()
{
char a;
char *str=&a;
strcpy(str,"hello");
printf(str);
return 0;
}
A.hello world!
B.HELLOWORLD
C.HELLO world!
D.HELLO
A、print("hello"+str(2020))
B、print("hello"+"world")
C、print("hello"+2020)
A、string str in myString
B、string s in myString
C、char str in myString
D、char s in myString
以下代码的运行结果是() public class Test{ String str=new String(“hello”); char ch[]={‘a’,’b’,’c’}; public static void main(String[] args) { Test ex=new Test(); Ex.change(ex.str , ex.ch); System.out.println(ex.str+“and”+ex.ch[0]); } public void change(String str , char ch[]){ str=”world”; ch[0]=’a’; } }
A、hello and d
B、hello and a
C、world and d
D、world and a
A.输出Hello,JavaScript!
B.输出Java
C.输出true
D.输出false
A.string str;
B.string str(“Hello, world” );
C.string str = “Hello, world”;
D.string str = ‘Hello, world’;
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