设Y=y(X)在点(0,1)处与抛物线:y=x2-x+1相切,并满足方程y"-3y'+2y=2ex,则y=y(x)=( ).
(A) e2x-xex(B) 2e2x-ex+xex
(C) (1-2x)ex(D) (1-x)ex
给定矢量函数,试求从点P₁(2,1,-1)到点P₂(8,2,-1)的线积分沿抛物线x=2y²(2)沿连接该两点的直线.这个E是保守场吗?
A.DSolve[2y[x]y"[x]==1+(y'[x])^2,y[0]==1,y'[0]==0,y[x],x
B.DSolve[{2y[x]y" [x]==1+(y'[x])^2,y[0]==1,y'[0]==0},y[x],x]
C.DSolve[{2y[x]y" [x]==1+(y^' [x])^2;y[0]==1;y'[0]==0},y[x],x]
D.DSolve[{2yy"==1+(y^' )^2&&y[0]==1&&y'[0]==0},y[x],x]
A.DSolve[2y[x]y"[x]==1+(y'[x])^2,y[0]==1,y'[0]==0,y[x],x
B.DSolve[{2y[x]y" [x]==1+(y'[x])^2,y[0]==1,y'[0]==0},y[x],x]
C.DSolve[{2y[x]y" [x]==1+(y^' [x])^2;y[0]==1;y'[0]==0},y[x],x]
D.DSolve[{2yy"==1+(y^' )^2&&y[0]==1&&y'[0]==0},y[x],x]
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