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[主观题]
计算题:有一个直径d0=10mm,L0=100mm低碳钢试样,拉伸试验时测得Fs=21KN,Fb=29KN,d1=5.95mm,L1=138mm.求此试样的屈服强度和抗拉强度
提问人:网友lixin080108
发布时间:2022-01-19
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S0=πdX102/4=3.14X102/4=78.5mm²
S1=πd1X2/4=3.14X5.65X2/4=25mm²
σs=Fs/S0=21000/78.5=267.5N/mm²
σb=Fb/S0=29000/78.5=369.4N/mm²
S1=πd1X2/4=3.14X5.65X2/4=25mm²
σs=Fs/S0=21000/78.5=267.5N/mm²
σb=Fb/S0=29000/78.5=369.4N/mm²
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