According to the strong version of the Sapir-Whorf hypothesis, speakers perceptions determ
此题为判断题(对,错)。
此题为判断题(对,错)。
According to Scheetz's statement(Para. 4), companies prefer ______.
A.people who have a strategic mind
B.people who are talented in fine arts
C.people who are ambitious and aggressive
D.people who have received training in mechanics
Write an order letter according to the following order sheet.
From: ABC Co.Ltd.
108 North Street
New York, America
12 May 2008
Order No.288
To: China National Import and Export Corp.
111 south street Shanghai, China
Qnty Item Catalogue No.N/P (CIF New York Net)
200 Bed Sheets, 150, blue AC66 US $6.00 each
300 Bed Sheets, 200, pink AC68 US $6.50 each
500 Pillow cases, blue ACT0 US $2.00 each
500 Pillow cases, pink AC76 US $2.00 each
US $2315.00
Packing: In cotton cloth Bales
Shipment : Prompt Shipment From shanghai
Payment: By …
China National Import and Export Corp
Purchase manager
求图的中心点。设V是有向图G的一个顶点, V的偏心度定义为: Find the central point of the graph. Let V be a vertex of the graph G, the definition of the eccentricity of V is: max{dist(w,v),∀w∈V(G)} 如果v是有向图G中具有最小偏心度的顶点,则称顶点v是G的中心点。 If the eccentricity of v is minimal in the graph G, then we call V a central point of G. 请从以下代码语句中选择正确的5条,填入空白处。按空白的标号顺序依次列出代码语句的标号,用一个空格分隔。如A F D H C Please choose 5 statements from the following, and put them into the blanks. List the number of the statement you choose according to the order of the blanks, and separate them with a single blank space. For instance, A F D H C. C++代码: void FLOYD_PXD(AdjMatrix g){ // 对以带权邻接矩阵表示的有向图g,求其中心点。 AdjMatrix w = g; for(k = 1; k <= n; k++) for(i="1;" i++) for(j="1;" j j++) if((1) ) (2) ; v="1;" dist="MAXINT;" j++){ s="0;" i (3) (4) ){ (5) } for printf("有向图g的中心点是顶点%d,偏心度%d\n", v, dist); }python代码:def floyd_pxd(adjmatrix g): adjmatrix w="g" k in range(1, n+1): range (1, if (): print("有向图g的中心点是" + str(v) ",顶点偏心度" str(dist)) 选项: src="http://static.jiandati.com/a9585d5-chaoxing2016-284362.png">
A.str[]=abdef
B.str[]=abcdef
C.str[]=a
D.str[]=ab
A.str[]=abdef
B.str[]=abcdef
C.str[]=a
D.str[]=ab
A.cin.get(str,strlen(str));
B.cin.getline(str,strlen(str));
C.cin>>str;
D.dn.read(str,strlen(str));
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