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Ln(-3+4i)=ln5+i(2kπ+π-arctan4/3)。()
Ln(-3+4i)=ln5+i(2kπ+π-arctan4/3)。()
提问人:网友yww2019
发布时间:2022-01-06
Ln(-3+4i)=ln5+i(2kπ+π-arctan4/3)。()
A.arg(-3+4i)=π一arctan4/3
B.arg(-3i)=arg(-i)
C.arg(-3+4i)2=2arg(-3+4i)
D.z·z=∣z-∣2
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