设变量m为float类型,变量n为int类型,则以下能实现将m中的数值保留小数点后两位,第三位进行四舍五入运算的表达式是()
A.m=(m*100+0.5)/100.0
B.n=m*100+0.5, m=n/100.0
C.n=m/100+0.5, m=n*100.0
D.m=m*100+0.5/100.0
A.m=(m*100+0.5)/100.0
B.n=m*100+0.5, m=n/100.0
C.n=m/100+0.5, m=n*100.0
D.m=m*100+0.5/100.0
A、m=n*100+0.5, n=m/100.0
B、n=n*100+0.5/100.0
C、n=(n*100+0.5)/100.0
D、n=(n/100+0.5)*100.0
A、n=(n*100+0.5)/l00.0
B、m=n*100+0.5, n=m/100.0
C、n=n*100+0.5/100.0
D、n=(n/100+0.5)*100.0
A、struct AA { int m,n; };
B、struct AA { int m,n; }aa;
C、struct { int m,n; };
D、struct { int m,n; }aa;
A、&refer_m=n;
B、*refer_m=*refer_n;
C、refer_m=refer_n;
D、&refer_m=&refer_n;
A、student.num=10002;
B、student.name="高远";
C、student.age=19;
D、student.score=90;
A、Student.Id
B、&(p->Id)
C、p->Id
D、stu.Id
A、A)a,2008
B、B)hangzhou,2008
C、C)i,2009
D、D)Tianjin,2009
A、struct student { long no; double score; };
B、struct stud[20] { long no; double score; };
C、struct student { long no; double score; }stud[20];
D、struct { long no; double score; } stud[100];
A、X=115
B、X=73
C、X=59.
D、X=72.
A、printf("%c\n","a");
B、printf("%c\n",'A'+32);
C、putchar(97);
D、putchar('a');
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