The rejection and not rejectance regions are divided by a point called the _______.
A、dividing point
B、critical value
C、rejection value
D、not rejectance value
A、dividing point
B、critical value
C、rejection value
D、not rejectance value
A、> 5
B、5
C、n = 60
D、< 5
A、a
B、b
C、1 – a
D、a / 2
A、are not mutually exclusive
B、are not collectively exhaustive
C、do not reference a population parameter
D、are established correctly
A、Computed test statistic = 2 and is greater than 1.645, so reject H0: µ ≤ 15.
B、Computed test statistic = 2 and is greater than 1.96, so reject H0: µ ≤ 15.
C、Computed test statistic = 2 and is greater than 1.753, so reject H0: µ = 15.
D、Computed test statistic = 2 and is greater than 2.131, so reject H0: µ ≤ 15.
A、it gets larger
B、it gets smaller
C、it does not change
A、-30
B、46
C、43
D、-13
A、–95.90 to 35.90
B、85.44 to 25.44
C、–76.53 to 16.53
D、–102.83 to 42.43
A researcher wants to conduct a before/after study on 11 subjects to determine if a treatment results in any difference in scores. The null hypothesis is that the average difference is zero while the alternative hypothesis is that the average difference is not zero. Scores are obtained on the subjects both before and after the treatment. After subtracting the after scores from the before scores, the average difference is calculated to be –2.40 with a sample standard deviation of 1.21. Assume that the differences are normally distributed in the population. The degrees of freedom for this test are _______.
A、11
B、10
C、9
D、20
A、do not reject the null hypothesis
B、reject the null hypothesis
C、take a larger sample
D、use the z-table instead of the t-table
Cowra Construction Company purchases steel rods for its projects. Based on previous tests, Clarrie Carter, Quality Assurance Manager, has recommended purchasing rods from Redding Rods (population 1), rather than Stockton Steel (population 2), since Redding’s rods had less variability in length. Recently, Stockton revised it rod shearing operation, and Clarrie has sampled the outputs from Redding’s and Stockton’s rod manufacturing processes. The results for Redding were s12 = 0.10 with n1 = 8, and, for Stockton, the results were s22 = 0.05 with n2 = 10. Assume that rod lengths are normally distributed in the population. Clarrie’s alternate hypothesis is __________________.
A、s12 = s22
B、s12 ≠ s22
C、s12 > s22
D、s12 < s22
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