题目内容 (请给出正确答案)
[主观题]

The flat fading will introduce ISI to the receiver.

提问人:网友dbdxyan1981 发布时间:2022-01-07
参考答案
  抱歉!暂无答案,正在努力更新中……
如搜索结果不匹配,请 联系老师 获取答案
更多“The flat fading will introduce…”相关的问题
第1题
If the bandwidth of the signal is less than the channel coherence bandwidth, then flat fading will occur.
点击查看答案
第2题
In a flat fading channel, the received signal is w...

In a flat fading channel, the received signal is writen aswhere x(t) and n(t) denote the transmit signal and the AWGN, respectively, andis the fading coefficient. Assume that the receiver has got the ideal channel estimate denoted byalso. a) Design a linear equalizer. b) Write the output of the equalizer.

点击查看答案
第3题
For multiple propagation, the correct statements include a. it probably introduces frequen
cy selective fading to the received signals. b. it probably introduces flat fading to the received signals. c. it will introduce fast fading to the received signals. d. It probably introduces ISI to the received signals.

A、对

B、对

C、对

D、对

点击查看答案
第4题
If B and Bc used to denote the bandwidth of the signal and the channel coherence bandwidth
, respectively, the correct statement is that a. if B>Bc, then the fast fading occurs. b. if B< Bc. then the fast fading occurs. c. if B>Bc. then the flat fading occurs.. d. if B<bc, then the flat fading> A、错。信号带宽和信道相干带宽的比较用于区分频率选择性衰落和平坦衰落

B、错。信号带宽和信道相干带宽的比较用于区分频率选择性衰落和平坦衰落

C、错。

D、对

点击查看答案
第5题
Write MATLAB codes to implement DSSS system sinmul...

Write MATLAB codes to implement DSSS system sinmulation, The system is a 2-user system with a 2-path frequency selective fadingchannel for each user, The power for each path is half the total transmit power for each user. A RAKR receiver with ideal channel estimation should be used in the receiver for each user. The relative delay between two paths is 1 chip. BPSK modulation is assumed. The BER-versus SNR curve should be drawn for both users. The SNR is defined by, and is assumed to change from 0 dB to 10 dB with step 1 dB. The simulation results should be compared with the theoretical BER versus SNR curve in flat Rayleigh fading channel.

A、N_Trials=300; N_number=100; N_snr=10; N_users=2; N_path=2; Delay=1; Q=16; N_samples=N_number*Q; E_M=0; for trials=1:N_Trials trials noise=randn(N_users.*N_path,Q*N_number)+j.*randn(N_users*N_path,Q*N_number); s10=round(rand(N_users,N_number)); ss_user=s10*2-1; % without consideration of delayed path pn01=round(rand(N_users,Q)); pn=(pn01.*2-1)./sqrt(Q); S_spread=[]; for user=1:N_users s=kron(ss_user(user,:), pn(user,:)); S_spread=[S_spread; s]; end S_multipath=[]; for user=1:N_users s_user=S_spread(user,:); Suser_delayed=[zeros(1,Delay), s_user(1,1:(N_samples-Delay))]; S_multipath=[S_multipath; [s_user;Suser_delayed]]; end %___________the following is to generate Rayleigh fading coefficients N=N_users.*N_path; fad_c=fading(8,0.005,N_samples, N); fad=fad_c.'; % only use the amplitude; %phase is not used, which is equivalent to have an ideal phase %compensation by using channel equalization S_spread=S_multipath.*fad; %S_spread is the signal matrix of size users x N_number sgma=1; Error_M=[ ]; for snr_db=0:1:N_snr snr=10.^(snr_db./10)/2; %Evaluate the SNR from SNR in dB N0=2*sgma.^2; Eb=snr.*N0; yy=sqrt(Eb./2)*S_spread+noise; %received spread signals in the baseband Error_v_user=[]; for user=1:N_users y_path1=yy((user-1).*N_path+1, :); y_path_temp=yy((user-1).*N_path+2, :); y_path2=[y_path_temp(1,Delay+1:N_samples), zeros(1,Delay)]; Y_M_path1=[ ]; Y_M_path2=[]; for k=1:N_number ym1=y_path1(1,(k-1)*Q+1:k*Q); ym2=y_path2(1,(k-1)*Q+1:k*Q); Y_M_path1=[Y_M_path1;ym1]; Y_M_path2=[Y_M_path2;ym2]; end % Y_M is a matrix of size N_number x Q, each row correspinding to a % BPSK symbol ys=Y_M_path1*pn(user,:).'+Y_M_path2*pn(user,:).'; %despreading for a user y=ys.'; y_real=real(y); s_e=sign(y_real); s_e10=(s_e+1)./2; Error_snr=sum(abs(s10(user,:)-s_e10)); Error_v_user=[Error_v_user;Error_snr./N_number]; %A BER collumn vector for all the users and for each snr end %for user Error_M=[Error_M,Error_v_user]; %BER matrix for all users and for all the SNRs end % end for snr E_M=E_M+Error_M ; end % end for trials BER=E_M./N_Trials; BER_T=[ ]; for snr_db=0:1:N_snr snr=10.^(snr_db./10); temp=sqrt(snr./(1+snr)); BER_THEROY=(1-temp)/2; BER_T=[BER_T,BER_THEROY]; end i=0:1:N_snr; semilogy(i,BER(1,:),'-r',i,BER(2,:),'ob',i,BER_T ,'*g'); xlabel('E_b/N_0(dB)') ylabel('BER') legend('User1 RAKE','User2 RAKE', 'Theoretical flat fading');

B、no need

C、no need

D、no need

点击查看答案
第6题
由于地形起伏或高大障碍物引起的衰落为:()

A.slow fading

B.fast fading

C.Rician fading

点击查看答案
第7题
We can infer from the text that the appearance of "immortal" life is ______ .A.a fading ho

We can infer from the text that the appearance of "immortal" life is ______ .

A.a fading hope

B.far from certain

C.just an illusion

D.only a matter of time

点击查看答案
第8题
When a speaker concludes a speech by fading out on an emotional note, she or he is using a __________ ending. (crescendo ending / dissolve ending)
点击查看答案
第9题
Her hope of her husband’s return is ________ as years go by.

A.narrowed down

B.fading

C.frank

D.schemes

点击查看答案
第10题
Many animals face extinction as the result of human ________.

A.fading

B.narrowed down

C.interference

D.frank

点击查看答案
账号:
你好,尊敬的用户
复制账号
发送账号至手机
密码将被重置
获取验证码
发送
温馨提示
该问题答案仅针对搜题卡用户开放,请点击购买搜题卡。
马上购买搜题卡
我已购买搜题卡, 登录账号 继续查看答案
重置密码
确认修改
欢迎分享答案

为鼓励登录用户提交答案,简答题每个月将会抽取一批参与作答的用户给予奖励,具体奖励活动请关注官方微信公众号:简答题

简答题官方微信公众号

警告:系统检测到您的账号存在安全风险

为了保护您的账号安全,请在“简答题”公众号进行验证,点击“官网服务”-“账号验证”后输入验证码“”完成验证,验证成功后方可继续查看答案!

微信搜一搜
简答题
点击打开微信
警告:系统检测到您的账号存在安全风险
抱歉,您的账号因涉嫌违反简答题购买须知被冻结。您可在“简答题”微信公众号中的“官网服务”-“账号解封申请”申请解封,或联系客服
微信搜一搜
简答题
点击打开微信