<select name=*>...</select>标记的作用是下拉菜单框。()
<select name=*>...</select>标记的作用是下拉菜单框。()
<select name=*>...</select>标记的作用是下拉菜单框。()
A、select (name) from table person: 所有记录的name字段的值
B、select (name) from person where age=12 or name=’aa‘; or 或者
C、select (name) from table person where age=12; 查找age=12的记录的那个字段的值
D、select (name,age) from person where age=12 and name=‘aa’; and 并且
A、select name from reviewer,rating where reviewer.rid=rating.rid group by reviewer.rid
B、select name from reviewer,rating where reviewer.rid=rating.rid having count(stars)>=3
C、select name from reviewer,rating group by reviewer.rid having count(stars)>=3
D、select name from reviewer,rating group by reviewer.rid where count(stars)>=3
A、select count(name) from stu;
B、select name,class from stu where name='pw';
C、select name,class,sex from stu where name='pw' and class='class-05-12';
D、select * from stu where class='class-05-12';
A、SELECT * FROM think_homeworkStatistics WHERE `name`='thinkphp' AND condition=1
B、SELECT * FROM think_homeworkStatistics WHERE `condition`='thinkphp' AND status=1
C、SELECT * FROM think_homeworkStatistics WHERE `condition`='thinkphp' OR condition=1
D、SELECT * FROM think_homeworkStatistics WHERE `name`='thinkphp' AND status=1
A、Select * From Student
B、Select Name From Student
C、Select Name,Age,IDCard From Student
D、Select Name Age IDCard Sex From Student
A. SELECT* FROM customers;
B. SELECT name, address FROM customers;
C. SELECT id, name, address, phone FROM customers;
D. SELECT cust_name, cust_address FROM customers;
E. SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
A、SELECT Name, HireDate FROM tblEmployees
B、SELECT Name, HireDate FROM tblEmployees WHERE HireDate =’2009-01-01’ OR ‘2009-12-31’
C、SELECT Name, HireDate FROM tblEmployees WHERE HireDate BETWEEN ’2008-12-31’ AND ‘2010-01-01’
D、SELECT Name, HireDate FROM tblEmployees WHERE substring(HireDate,1,4)=2009;
Examine the description of the EMPLOYEES table:EMP_ID NUMBER(4) NOT NULLLAST_NAME VARCHAR2(30) NOT NULLFIRST_NAME VARCHAR2(30)DEPT_ID NUMBER(2)Which statement produces the number of different departments that have employees with last name Smith? ()
A. SELECT COUNT (*) FROM employees WHERE last _name=‘smith‘;
B. SELECT COUNT (dept_id) FROM employees WHERE last _name=‘smith‘;
C. SELECT DISTINCT (COUNT (dept_id) FROM employees WHERE last _name=‘smith‘;
D. SELECT COUNT (DISTINCT dept_id) FROM employees WHERE last _name=‘smith‘;
E. SELECT UNIQE (dept_id) FROM employees WHERE last _name=‘smith‘;
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