题目内容
(请给出正确答案)
[主观题]
求微分方程(1+y)dx-(1-x)dy=0的通解.
求微分方程(1+y)dx-(1-x)dy=0的通解.
提问人:网友wuxuesong
发布时间:2022-01-07
求微分方程(1+y)dx-(1-x)dy=0的通解.
B、y=dsolve('Dy=x+y+1')
C、y=dsolve('Dy=x+y+1'; 'x')
D、y=dsolve('Y'=x+y+1', 'x')
求解常微分方程, 应用的语句是
A、Solve[(x^2+1)y"[x]==2x*y'[x],y[x],x]
B、DSolve[(x^2+1)y" [x]=2x*y'[x],y[x],x]
C、DSolve[(x^2+1)y" [x]==2x*y'[x]]
D、DSolve[(x^2+1)y" [x]==2x*y'[x],y[x],x]
A.(-1,1)
B.[0,1/2]
C.(0,1)
D.(0,1/2)
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