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试证明: 函数f(x,y)=(x2-y2)/(x2+y2)2((x,y)≠(0,0)),f(0,0)=0在[0,1]×[0,1]上不可积.
试证明:
函数f(x,y)=(x2-y2)/(x2+y2)2((x,y)≠(0,0)),f(0,0)=0在[0,1]×[0,1]上不可积.
提问人:网友anonymity
发布时间:2022-01-06
试证明:
函数f(x,y)=(x2-y2)/(x2+y2)2((x,y)≠(0,0)),f(0,0)=0在[0,1]×[0,1]上不可积.
设f(x)是[0,1]上正值递增函数,若有g(x)满足0≤g(x)≤[f(x)-f(y)]/(x-y)(0<y<x≤1),则存在(0,1)上递减可积函数F(x),使得g(x)≤F(x)(0<x<1).
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